The balanced equation of mercury (ii) oxide is: 2Hg(l) + O2(g) → 2 HgO(s)
as the original equation between Oxygen and Mercury to form Mercury(ii)oxide is: Hg(l) + O2(g) → HgO(s) and we start to compare first, O atom number on both sides of the equation: we find 2 atoms on the right side and 1 in the left side so, we put 2HgO instead of HgO to make the number of O equals on each side so the equation become Hg + O2 → 2HgO then we start to compare the Hg atom number on each side: we find 1 Hg on the right side and 2 Hg on the left side So, we put 2Hg instead of Hg to make the number of Hg atoms equals in each side. So we get our final balanced equation is: 2Hg(l) + O2(g) → 2HgO (s)
